A) 310 nm
B) 620 nm
C) 6200 nm
D) 3100 nm
Correct Answer: B
Solution :
The threshold wavelength is \[{{W}_{0}}=\frac{hc}{{{\lambda }_{0}}}\Rightarrow {{\lambda }_{0}}=\frac{hc}{{{W}_{0}}}\] ?(i) Now, putting the given value in Eq. (i) \[{{\lambda }_{o}}=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{2\times 1.6\times {{10}^{-19}}}\] \[=618.75\times {{10}^{-9}}\approx 620\,mm\]
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