A) -13.6 eV
B) 13.6 eV
C) -27.2 eV
D) -6.8 eV
Correct Answer: A
Solution :
Kinetic energy of the electron in nth orbit of hydrogen atom is \[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}\] In \[n=1\]orbit \[{{E}_{1}}=-\frac{13.6}{{{(1)}^{2}}}=-13.6\]
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