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EAMCET Medical EAMCET Medical Solved Paper-1998

  • question_answer
    Plutonium decays with a half-life of 24000 years. If plutonium is stored for 72000 years, the fraction of it that remains is:

    A)  \[\frac{1}{2}\]                                  

    B)  \[\frac{1}{3}\]

    C)  \[\frac{1}{4}\]                                  

    D)  \[\frac{1}{8}\]

    Correct Answer: D

    Solution :

                     No. of half - lives n \[n=\frac{t}{T}=\frac{72000}{24000}=3\] From relation, \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}={{\left( \frac{1}{2} \right)}^{3}}=\frac{1}{8}\]


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