A) \[4,0,1,\frac{1}{2}\]
B) \[4,1,0,\frac{1}{2}\]
C) \[4,0,0,\frac{1}{2}\]
D) \[4,1,1,\frac{1}{2}\]
Correct Answer: C
Solution :
The electronic configuration of potassium (At. no. 19) is: \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}},4{{s}^{1}}\] The valence electron is present in \[4{{s}^{1}}.\] Hence, quantum numbers for \[4{{s}^{1}}\] are : n (Principal quantum no.) = 4 \[l\] (Azimuthal quantum no.) = 0 Note: for s sub shell \[l=0\] for p sub shell \[l=1\] for d sub shell \[l=2\] for \[f\]sub shell \[l=3\] m (magnetic quantum no.) = 0 The value of m depends upon \[l.\] s (spin quantum no.) \[=+\frac{1}{2}.\]
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