EAMCET Medical EAMCET Medical Solved Paper-1998

  • question_answer
    According to VSEPR theory the shape of the water molecule is:

    A)  linear                                   

    B)  planar triangle

    C)   F-shaped          

    D)  octahedral

    Correct Answer: C

    Solution :

                     The central atom in water, oxygen is in a state of \[s{{p}^{2}}-\]hybridization. The four \[s{{p}^{3}}\]orbitals should be tetrahedral mutually  inclined at an angle of \[{{109}^{o}}\text{ }28,\] out of the  four hybrid orbitals, two singly filled orbitals overlap with s orbitals of hydrogen forming two 0?H bonds. Remaining two non-bonding orbitals each containing a lone pair, occupy more space and compress the two bond pairs. The bond angle decreases from \[{{109}^{o}}\text{ }28\]to \[{{104.5}^{o}}.\] Therefore, water molecule is V shaped with bond angle \[\text{104}\text{.}{{\text{5}}^{\text{o}}}\text{.}\]


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