A) 2.016
B) 20.16
C) 2.24
D) 22.4
Correct Answer: A
Solution :
\[\underset{\text{Mol}\text{.wt = 100}}{\mathop{CaC{{O}_{3}}}}\,\xrightarrow{\Delta }CaO+\underset{\begin{smallmatrix} \text{22}\text{.4}\,\text{L}\,\text{at}\,\text{STP} \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\text{1}\,\text{mole} \end{smallmatrix}}{\mathop{C{{O}_{2}}}}\,\] Wt. of 10g of 90% pure limestone \[=\frac{10\times 90}{100}=9\] g pure \[CaC{{O}_{3}}\] \[\because \]100 g\[CaC{{O}_{3}}\]on heating at STP evolve \[C{{O}_{2}}\] \[=22.4\,L\] \[\therefore \]9 g \[CaC{{O}_{3}}\]on heating at STP evolve \[C{{O}_{2}}=\frac{22.4\times 9}{100}=2.016\,L\]
You need to login to perform this action.
You will be redirected in
3 sec
