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EAMCET Medical EAMCET Medical Solved Paper-1998

  • question_answer
    The dissociation constant of a weak monobasic acid \[{{K}_{a}}\]is \[1\times {{10}^{-5}}.\] The pH of \[0.1\,\text{M}\]of that acid would be:

    A)  3                                            

    B)  between 2-3

    C)  1                                            

    D)  5

    Correct Answer: A

    Solution :

                     \[{{K}_{a}}=1\times {{10}^{-5}}\] Concentration (c or M) = 0.1 M \[pH=-\log [{{H}^{+}}]\]                \[[{{H}^{+}}]=\sqrt{{{K}_{a}}\times M}\] \[=\sqrt{1\times {{10}^{-5}}\times 0.1}\] \[=1\times {{10}^{-3}}\]                 \[\therefore \]  \[pH=-\log {{10}^{-3}}\]                                 \[=3\]


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