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EAMCET Medical EAMCET Medical Solved Paper-1998

  • question_answer
    The weight of \[\text{AgN}{{\text{O}}_{\text{3}}}\] (mol. wt. 170) present in 100 mL of its 0.25 M solution is :

    A)  4.25 g                                  

    B)  42.5g

    C)  17g                                       

    D)  1.7g

    Correct Answer: A

    Solution :

                     We know that \[m=\frac{EVN}{1000}\] Where,       m = wt.                 E = Eq. wt. V = Volume in mL N = Normality For \[\text{AgN}{{\text{O}}_{\text{3}}}\]molarity equals to normality  then, For \[\text{AgN}{{\text{O}}_{3}}\]mol. wt. = Eq. wt. \[E=170\] \[V=100\,\,mL\] \[N=0.25\] \[m=\frac{170\times 100\times 0.25}{1000}=4.25\,g\]


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