A) \[Na\]
B) \[Na/liq.N{{H}_{3}}\]
C) \[Na/dry\]ether
D) Na/dry alcohol
Correct Answer: C
Solution :
Wurtz reaction: Alkyl halides when heated with metallic sodium in ether solution gives higher alkanes by joining the two alkyi groups. \[2R.X+2Na\xrightarrow{\text{Ether}}R.R+2NaX\] So, the reagent is Na /dry ether.
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