A) \[{{O}_{2}}\]
B) \[{{\text{H}}_{2}}\]
C) \[Cl{{O}_{2}}\]
D) \[HOCl\]
Correct Answer: A
Solution :
Chlorine is reduced by \[{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}\]as under: \[C{{l}_{2}}+{{H}_{2}}{{O}_{2}}\xrightarrow{{}}2HCl+{{O}_{2}}\]\[{{\text{O}}_{\text{2}}}\]gas is evolved in this reaction.
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