A) azo benzene
B) aniline
C) N-phenyl hydroxyl amine
D) hydrazobenzene
Correct Answer: C
Solution :
Reduction of nitrobenzene in neutral medium: \[Zn/N{{H}_{4}}Cl\] or \[Zn/CaC{{l}_{2}}\]reduce a nitro compound to hydroxyl amine. \[{{C}_{6}}{{H}_{5}}N{{O}_{2}}+2Zn+4N{{H}_{4}}Cl\xrightarrow{{}}\] \[\underset{\text{Phenyl}\,\text{hydroxyl}\,\text{amine}}{\mathop{{{C}_{6}}{{H}_{5}}NHOH}}\,+2ZnC{{l}_{2}}+{{H}_{2}}O+4N{{H}_{3}}\] Phenyl hydroxyl amine
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