A) \[CHC{{l}_{3}}\]
B) \[CC{{l}_{3}}CHO\]
C) \[C{{H}_{2}}Cl\]
D) \[C{{H}_{3}}Cl\]
Correct Answer: A
Solution :
When chlorine reacts with ethyl alcohol in presence of NaOH, chloroform is obtained. \[C{{H}_{3}}C{{H}_{2}}OH+C{{l}_{2}}\xrightarrow{{}}C{{H}_{3}}CHO+2HCl\] \[C{{H}_{3}}CHO+3C{{l}_{2}}\xrightarrow{{}}\underset{\text{Chloral}}{\mathop{C.C{{l}_{3}}.CHO}}\,+3HCl\] \[2C.C{{l}_{3}}.CHO+NaOH\xrightarrow{{}}\underset{\text{Chloroform}}{\mathop{2CHC{{l}_{3}}}}\,\] \[+HCOONa\]
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