A) Diethyl ether \[\xrightarrow{\text{reduction}}X\xrightarrow{SOC{{l}_{2}}}\]
B) Diethyl ether \[+\,\text{HI}\to \]
C) Diethyl ether \[\text{+ PC}{{\text{l}}_{\text{5}}}\to \]
D) Diethyl ether \[\text{+ C}{{\text{l}}_{\text{2}}}\to \]
Correct Answer: D
Solution :
Diethyl ether reacts with chlorine does not give alkyi halide because oxygen atom in diethyl ether is more electronegative than chlorine. Therefore, chlorine cannot break the bond of diethyl ether.
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