A) frequency
B) \[\frac{1}{\text{frequency}}\]
C) velocity
D) acceleration
Correct Answer: B
Solution :
Dimensions of\[\frac{m}{BQ}\] \[\text{=}\frac{\text{Dimensinons}\,\text{of}\,\text{m}}{\text{(Dimensions}\,\text{of}\,\text{B)(dimensions}\,\text{of}\,\text{Q)}}\] \[\frac{m}{BQ}=\frac{[M]}{[M{{L}^{0}}{{T}^{-2}}{{A}^{-1}}][{{M}^{0}}{{L}^{0}}TA]}=\frac{1}{[{{T}^{-1}}]}\] \[\text{=}\,\frac{\text{1}}{\text{frequecy}}\]
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