A) 1 : 2 : 3
B) 1 : 2 : 4
C) 1 : 3 : 5
D) 1 : 5 : 9
Correct Answer: C
Solution :
Distance travelled by the body in \[{{t}^{th}}\]sec \[{{s}_{{{t}^{th}}}}=u+\frac{1}{2}a(2t-1)\] ?(i) Now, distance travelled in \[{{\text{I}}^{\text{st}}}\]second from rest \[{{s}_{1}}=0\frac{1}{2}a(2\times 1-1)\] \[{{s}_{1}}=\frac{1}{2}a\] ?(ii) Now, distance travelled in \[{{\text{2}}^{\text{nd}}}\]second from rest \[{{s}_{2}}=0+\frac{1}{2}a(2\times 2-1)\] \[{{s}_{2}}=\frac{3a}{2}\] ?(iii) Now, distance travelled in 3rd second from rest \[{{s}_{3}}=0+\frac{1}{2}a(2\times 3-1)\] \[{{s}_{3}}=\frac{5a}{2}\] ?(iv) Now, from Eqs. (ii), (iii) and (iv), we have \[{{s}_{1}}:{{s}_{2}}:{{s}_{3}}=1:3:5\]
You need to login to perform this action.
You will be redirected in
3 sec
