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EAMCET Medical EAMCET Medical Solved Paper-1999

  • question_answer
    A stone is dropped freely, while another is thrown vertically downward with an initial velocity at 2 m/s from the same point, simultaneously. The time required by them to have a distance of separation 22 m between them is:

    A)  11 s                                      

    B)  5.5 s

    C)  44 s                                      

    D)  22 s

    Correct Answer: A

    Solution :

                     Given: distance of separation = 22 m u = 2 m/s From the formula, distance = velocity \[\times \] time or           \[{{s}_{1}}-{{s}_{2}}=ut\]                 \[22=ut=2\times t\]                 \[\therefore \]  \[t=\frac{22}{2}=11\,s\]


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