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EAMCET Medical EAMCET Medical Solved Paper-1999

  • question_answer
    A person of 70 kg mass is lifted by a helicopter with the help of rope, hanging from it. If the helicopter is rising up with an acceleration \[4\text{ }m{{s}^{-2}},\] the tension in the rope is (taking\[g=10m{{s}^{-2}}\]):

    A)  250 N                                   

    B)  490 N

    C)  980 N                                   

    D)  1960 N

    Correct Answer: C

    Solution :

                     When helicopter is rising upward the tension in the rope is given by \[T=m(g+a)\] (Where a is acceleration of helicopter by which it is rising) Given: Mass of the person m = 70 kg accelerations\[a=4m/{{s}^{2}},\,g=10m/{{s}^{2}}\] Now, putting the given values in Eq. (i), we     have \[T=70\text{ (}10+4\text{)}=70\times 14=980\text{ }N\]


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