A) \[4{}^\circ C\]
B) \[9{}^\circ C\]
C) \[12{}^\circ C\]
D) \[16{}^\circ C\]
Correct Answer: D
Solution :
Heat given = Heat taken \[{{m}_{1}}{{s}_{1}}{{t}_{1}}+{{m}_{2}}{{s}_{2}}{{t}_{2}}={{m}_{1}}{{s}_{1}}t+{{m}_{2}}{{s}_{2}}t\] ?(i) Given: \[{{m}_{1}}{{s}_{1}}:{{m}_{2}}{{s}_{2}}=1:3\] \[{{t}_{1}}=100\]also \[{{t}_{2}}=?,t=37{{\,}^{o}}C\] Now, putting the given value \[1\times 100+3{{t}_{2}}=1\times t+3\times t\] \[100+3{{t}_{2}}=4\times 37\] \[3{{t}_{2}}=148-100\] \[{{t}_{2}}=\frac{48}{3}=16{{\,}^{o}}C\]
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