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EAMCET Medical EAMCET Medical Solved Paper-1999

  • question_answer
    20 g of ice and 20 g of hoi water are mixed. When the ice is melted the temperature of the mixture was found to be \[0{}^\circ C\]. The temperature of hot water taken should (L = 80 cal/g):

    A) \[40{}^\circ C\]                                 

    B) \[72{}^\circ C\]

    C) \[80{}^\circ C\]                                 

    D) \[96{}^\circ C\]

    Correct Answer: C

    Solution :

                     From the relation, \[mL=ms({{t}_{1}}-{{t}_{2}})\]                    (Here \[{{t}_{2}}=0\]) \[20\times 80=20\times {{t}_{2}}\] \[{{t}_{2}}=\frac{80\times 20}{20}\] \[=80{{\,}^{o}}C\]


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