A) 1.25 g
B) 5 g
C) 10 g
D) 20 g
Correct Answer: C
Solution :
Since, mass of water \[\propto \]radius of capillary tube \[m\propto r\] \[\frac{{{m}_{2}}}{{{m}_{1}}}=\frac{{{r}_{2}}}{{{r}_{1}}}\] \[{{m}_{2}}=\frac{{{r}_{2}}}{{{r}_{1}}}\times {{m}_{1}}\] \[=\frac{2r}{r}\times 5\] \[=10\,g\]You need to login to perform this action.
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