A) \[40{}^\circ C\]
B) \[72{}^\circ C\]
C) \[80{}^\circ C\]
D) \[96{}^\circ C\]
Correct Answer: C
Solution :
From the relation, \[mL=ms({{t}_{1}}-{{t}_{2}})\] (Here \[{{t}_{2}}=0\]) \[20\times 80=20\times {{t}_{2}}\] \[{{t}_{2}}=\frac{80\times 20}{20}\] \[=80{{\,}^{o}}C\]You need to login to perform this action.
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