A) \[C{{r}^{3+}}\]
B) \[M{{n}^{2+}}\]
C) \[N{{i}^{2+}}\]
D) \[F{{e}^{3+}}\]
Correct Answer: C
Solution :
Atomic no. of vanadium = 23 Its configuration is \[{{\,}_{23}}V=[Ar]3{{d}^{3}},4{{s}^{2}}\] \[{{V}^{3+}}=[Ar]3{{d}^{2}}\] \[\text{N}{{\text{i}}^{\text{2+}}}\]also has 2 unpaired electrons.You need to login to perform this action.
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