A) \[20\pi \]
B) \[\frac{1}{20\,\pi }\]
C) \[\frac{1}{10\,\pi }\]
D) \[10\,\pi \]
Correct Answer: C
Solution :
From the relation, \[{{v}_{\max }}=A\omega \]` ?(i) and \[{{a}_{\max }}=A{{\omega }^{2}}\] ?(ii) The ratio is obtained or dividing Eqs. (i) and (ii) \[\frac{{{v}_{\max }}}{{{a}_{\max }}}=\frac{A\omega }{A{{\omega }^{2}}}=\frac{1}{\omega }\] ?(iii) Equation of SHM is given \[x=0.5\sin (10\pi t+1.5x).\cos (10\pi t+1.5x)\] So, from above equation \[\omega =10\pi \] Now, putting the value of \[\omega =10\pi \]in Eq. (iii) \[\frac{{{v}_{\max }}}{{{a}_{\max }}}=\frac{1}{10\pi }\]You need to login to perform this action.
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