A) \[Y=\frac{5}{18}K\]
B) \[Y=\frac{5}{8}\eta \]
C) \[Y=\frac{9}{5}K\]
D) \[Y=\frac{18}{5}K\]
Correct Answer: D
Solution :
Given: \[\eta =2K.\] The relation between Y,K and \[\eta \]is expressed as \[Y=\frac{9K\eta }{3K+\eta }\] Now, putting the given value \[\eta =2K\]in above expression, we obtain \[Y=\frac{9K\times 2K}{3K+2K}=\frac{18{{K}^{2}}}{5K}=\frac{18K}{5}\]You need to login to perform this action.
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