A) \[3.125\times {{10}^{18}}\]per min
B) \[3.125\times {{10}^{17}}\]per sec
C) \[3.125\times {{10}^{17}}\]per min
D) \[3.125\times {{10}^{18}}\]per sec
Correct Answer: D
Solution :
\[Power=\frac{No.\,of\,fissions\times energy}{Time}\] \[\frac{n}{t}=\frac{power}{energy}=\frac{100\times {{10}^{6}}}{200\times {{10}^{6}}\times 1.6\times {{10}^{-19}}}\] \[=3.125\times {{10}^{18}}\text{per}\,\text{sec}\]
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