A) 2.303
B) 0.2303
C) 0.02303
D) 23.03
Correct Answer: B
Solution :
Decomposition of \[{{\text{N}}_{\text{2}}}{{\text{O}}_{\text{5}}}\]is a first order reaction. \[K=\frac{2.303}{t}\log \frac{a}{(a-x)}\]where a = Initial concentration \[(a-x)=\]Remaining concentration or \[t=\frac{2.303}{k}\log \frac{a}{(a-x)}\] For 90% completion of the reaction \[{{t}_{90%}}=\frac{2.303}{k}\log \frac{100}{100-90}\] \[=\frac{2.303}{k}\log 10\] \[(\because \,{{t}_{90%}}=10\min )\] \[10=\frac{2.303}{k}\log 10\] \[k=\frac{2.303}{10}=0.2303\,{{\min }^{-1}}\]You need to login to perform this action.
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