A) 40
B) 4
C) 0.4
D) 20
Correct Answer: C
Solution :
\[\because \] pH of \[NaOH=12\] \[\therefore \]\[pOH=14-12=2\] \[[O{{H}^{-}}]={{10}^{-pOH}}={{10}^{-2}}\] \[={{10}^{-2}}\,M\] Volume of NaOH solution =1 L Molarity \[\text{= }\frac{\text{Wt}\text{.of}\,\text{solute}}{\text{Mol}\text{.wt}\text{.of}\,\text{solute}\,\,\text{ }\!\!\times\!\!\text{ }\,\text{volume}\,\text{(in}\,\text{litre)}}\] Mol. Wt. of \[\text{NaOH}\,\text{=}\,\text{23+16 + 1 = 40}\] \[\text{0}\text{.01=}\frac{\text{Wt}\text{.of solute}}{\text{40}\,\text{ }\!\!\times\!\!\text{ 1}}\] Wt. of solute or \[\text{NaOH}\,\text{=}\,\text{0}\text{.01}\times \text{40}\,\text{=}\,\text{0}\text{.4}\,\text{g}\]
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