A) 300
B) 30
C) 0.3
D) 3
Correct Answer: B
Solution :
\[T=27+273=300K\] \[P=0.821\,\text{atm}\] \[V=?\] \[R=0.0821\,\text{Latm}\,\text{mo}{{\text{l}}^{-1}}\,{{\text{K}}^{-1}}\] \[n=1\,mol\] \[PV=nRT\] \[V=\frac{nRT}{P}\] \[=\frac{1\times 0.0821\times 300}{0.821}=30\,L\]You need to login to perform this action.
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