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EAMCET Medical EAMCET Medical Solved Paper-1999

  • question_answer
    6 g of urea is dissolved in 16.2 g of water at \[\text{25}{{\,}^{\text{o}}}\text{C}\text{.}\] What is the vapour pressure (in mm) of resulting solution? The vapour pressure of water at \[\text{25}{{\,}^{\text{o}}}\text{C}\text{.}\]is 24 mm:

    A)  24                                         

    B)  21.3

    C)  23.6                                      

    D)  18

    Correct Answer: B

    Solution :

                     V.P. of pure solvent (P) = 24 Wt. of solute (urea) = 6 Wt. of solvent (water) =16.2 V.P. of solution \[({{P}_{s}})=?\] Mol. wt. of urea = 60 According to Raoults law \[\frac{P-{{P}_{s}}}{P}=\frac{w}{m}\times \frac{M}{W}\] \[\frac{24-{{P}_{s}}}{24}=\frac{6}{60}\times \frac{18}{16.2}\] \[{{P}_{s}}=21.3\]


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