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EAMCET Medical EAMCET Medical Solved Paper-1999

  • question_answer
    Standard reduction potentials of \[S{{n}^{2+}}/Sn\]and \[Z{{n}^{2+}}/Zn\]electrodes are 0.14 V and \[-\text{ }0.74\text{ V}\] respectively. What is the \[{{\text{E}}^{\text{o}}}\] of the following cell in volts \[\text{Zn/Z}{{\text{n}}^{2+}}||S{{n}^{2+}}/Sn\]?

    A)  \[-0.6\]                               

    B)  \[-0.88\]

    C)  0.88                                      

    D)  0.6

    Correct Answer: D

    Solution :

                     \[{{E}^{o}}_{cell}={{E}_{cathode}}-{{E}_{anode}}\] \[{{E}_{cathode(S{{n}^{2+}}/Sn)}}=-0.14\] \[{{E}_{anode(Z{{n}^{2+}}/Zn)}}=-0.74\] \[{{E}^{o}}_{cell}=-0.14-(-0.74)\] \[=0.74-0.14\] \[=0.6\,\text{V}\]


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