question_answer

The compound formed when nitrobenzene is reduced with \[\text{LiAl}{{\text{H}}_{\text{4}}}\] is:

A)  \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\]

B)  \[{{C}_{6}}{{H}_{5}}-NHOH\]

C)  \[{{C}_{6}}{{H}_{5}}N=N{{C}_{6}}{{H}_{5}}\]

D)  \[{{C}_{6}}{{H}_{5}}NHNH{{C}_{6}}{{H}_{5}}\]

Correct Answer: C

Solution :

                 When nitrobenzene is reduced with \[\text{LiAl}{{\text{H}}_{\text{4}}}\] azobenzene is obtained as: