A) \[1.5\times {{10}^{17}}\]
B) \[3\times {{10}^{19}}\]
C) \[1.5\times {{10}^{25}}\]
D) \[3\times {{10}^{25}}\]
Correct Answer: A
Solution :
Power output \[P=4.8\,MW\] \[=4.8\times {{10}^{6}}J/s\] \[=\frac{4.8\times {{10}^{6}}}{1.6\times {{10}^{-19}}}=3\times {{10}^{25}}\,eV/s\] \[=\frac{3\times {{10}^{25}}}{{{10}^{6}}}=3\times {{10}^{9}}\,MeV/s\] Energy released per fission of \[{{\text{U}}^{\text{235}}}\] =200 MeV Hence, No. of fissions per second \[=\frac{3\times {{10}^{19}}\,MeV}{200\,MeV}\] \[=1.5\times {{10}^{17}}\]
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