EAMCET Medical EAMCET Medical Solved Paper-2000

  • question_answer
    When the temperature of an ideal gas is increased by 600 K, the velocity of sound in the gas becomes \[\sqrt{3}\]times the initial velocity in it. The initial temperature of the gas is:

    A) \[-73{}^\circ C\]                               

    B) \[27{}^\circ C\]

    C) \[127{}^\circ C\]

    D) \[327{}^\circ C\]

    Correct Answer: B

    Solution :

                     Let initial temperature is T ie            \[{{T}_{1}}=T\] Then,      \[{{T}_{2}}=T+600\] Velocity of sound in gas \[v\propto \sqrt{T}\] \[\frac{{{v}_{2}}}{{{v}_{1}}}=\sqrt{\frac{{{T}_{2}}}{{{T}_{1}}}}\]                 According to questions \[{{v}_{2}}=\sqrt{3}{{v}_{1}}\] \[\frac{\sqrt{3}{{v}_{1}}}{{{v}_{1}}}=\sqrt{\frac{T+600}{T}}\] \[\sqrt{3}=\sqrt{\frac{T+600}{T}}\]                 \[\therefore \]  \[3T=T+600\]                                 \[T=300\,K\] \[=300-273\,=27{{\,}^{o}}C\]


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