A) force
B) power
C) pressure
D) acceleration
Correct Answer: D
Solution :
\[\frac{Energy}{Mass\times length}=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[M][L]}=[L{{T}^{-2}}]\] Force (F) = Mass(m) \[\times \] acceleration \[\therefore \] \[[F]=[M][L{{T}^{-1}}]\] \[=[ML{{T}^{-1}}]\] Power (P) = Force (F) \[\times \]velocity (v) \[\therefore \] \[[P]=[ML{{T}^{-2}}][L{{T}^{-1}}]\] \[=[M{{L}^{2}}{{T}^{-3}}]\] Pressure (p) \[\text{(P) = }\frac{\text{Force (F)}}{\text{Area (A)}}\] \[\therefore \] \[[p]=\frac{[ML{{T}^{-2}}]}{[{{L}^{2}}]}=[M{{L}^{-1}}{{T}^{-2}}]\] Acceleration \[\text{(a) =}\frac{\text{Forece }\!\![\!\!\text{ F }\!\!]\!\!\text{ }}{\text{Mass(m)}}\] \[\Rightarrow \] \[[a]=\frac{[ML{{T}^{-2}}]}{[m]}=[L{{T}^{-2}}]\] So, choice is correct.
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