EAMCET Medical EAMCET Medical Solved Paper-2000

  • question_answer
    A long straight wire carries an electric current of 2A. The magnetic induction at a perpendicular distance of 5 m from the wire is: \[\left[ {{\mu }_{0}}=4\pi \times {{10}^{-7}}T \right]\]

    A)  \[4\times {{10}^{-8}}T\]                              

    B)  \[8\times {{10}^{-8}}T\]

    C)  \[12\times {{10}^{-8}}T\]                            

    D)  \[16\times {{10}^{-8}}T\]

    Correct Answer: B

    Solution :

                     \[i=2A,\,r=5\,m\] Magnetic field due to a straight wire \[B=\frac{{{\mu }_{0}}i}{2\pi r}\] \[=\frac{4\pi \times {{10}^{-7}}\times 2}{2\pi \times 5}\] \[=\frac{2\times {{10}^{-7}}\times 2}{5}\] \[=0.8\times {{10}^{-7}}\] \[=8\times {{10}^{-8}}T\]


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