question_answer

Two charges of 4\[\mu \]C each are palced at the corners of A and B of an equilateral triangle ABC of side length 0.2 m in air. The electric potential is: \[\left[ \frac{1}{4\pi {{\varepsilon }_{0}}}=9\times {{10}^{9}}\frac{N-{{m}^{2}}}{{{C}^{2}}} \right]\]

A) \[9\times {{10}^{4}}V\]                                

B)  \[18\times {{10}^{4}}V\]

C) \[12\times {{10}^{4}}V\]                              

D)  \[72\times {{10}^{4}}V\]