A) 48
B) 58
C) 60
D) 70
Correct Answer: B
Solution :
Given: Surface temperature \[(b=0.0029\,mK)T=5\times {{10}^{4}}K\] Applying, Weins displacement law \[{{\lambda } {m}}T=b=cons\tan t\] \[{{\lambda }_{m}}\times 5\times {{10}^{4}}=0.0029\] \[{{\lambda }_{m}}=\frac{0.0029}{5\times {{10}^{4}}}=58\times {{10}^{-9}}m\] \[=58\,nm\]You need to login to perform this action.
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