A) 4400
B) 3200
C) 4800
D) 1524
Correct Answer: C
Solution :
\[E=\frac{3}{2}nRT\] Where, E = Kinetic energy n = number of moles = 4 R = Gas constant =2cal/mol/K T = Temperature in Kelvin = 127 + 273 = 400K \[E=\frac{3}{2}\times 4\times 2\times 400\] = 4800 calorieYou need to login to perform this action.
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