A) 100
B) 150
C) 250
D) 300
Correct Answer: B
Solution :
Given: Resistance of galvanometer \[G=100\Omega \] Number of division contained = 25 division Value of current \[i=4\times {{10}^{-4}}\]amp/division Value of \[i\] for 25 division \[{{i}_{g}}=4\times 25\times {{10}^{-4}}={{10}^{-2}}A\] \[V=2.5\,\text{volt}\] From the relation to convert galvanometer into voltmeter the shunt resistance R is given \[R=\left[ \frac{V}{{{i}_{g}}}-G \right]\] \[R=\left( \frac{2.5}{{{10}^{-2}}}-100 \right)=250-100\] \[R=150\Omega \]You need to login to perform this action.
You will be redirected in
3 sec