A) 234
B) 377
C) 432
D) 218
Correct Answer: A
Solution :
Total no. of rabbits = 650 Number if rabbits with recessive alleles = 390 According to law of Hardy- Wleinberg equilibrium Forallelic frequency \[{{(A+a)}^{2}}=1\] ?(1) for genotypic frequency \[AA\text{ }+\text{ }2Aa\text{ }+\text{ }aa=\text{ }1\] ...(2) where A = frequency of dominant allele a= frequency of recessive allele The frequency of recessive allele\[a=\frac{390}{650}=0.6\] from equation (1), frequency of other allele A + a= 1 A = 1- 0.6 = 0.4 frequency for occurring of homozygous (aa)\[=0.6\times 0.6=0.36\] So the number of genotypes with (aa) = \[650\times 0.36=234.\]
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