A) \[\frac{6}{\sqrt{5}}\]
B) \[\frac{8}{\sqrt{5}}\]
C) \[\frac{12}{\sqrt{5}}\]
D) \[\frac{16}{\sqrt{5}}\]
Correct Answer: B
Solution :
Given: \[Q=8\,units\] \[\vec{R}=2\vec{P}\] Since, \[\vec{R}\] is along Y-axis and \[\vec{P}\]is along \[x-\]axis. Therefore, \[\vec{P}\]and \[\vec{R}\] is perpendicular vectors. Hence, \[{{Q}^{2}}={{R}^{2}}+{{P}^{2}}\] Putting the given values in Eq. (i), we get \[{{(8)}^{2}}={{(2p)}^{2}}+{{p}^{2}}=4{{p}^{2}}+{{P}^{2}}=5{{p}^{2}}\] or \[5{{p}^{2}}=64\] \[{{P}^{2}}=\frac{64}{5}\] \[\therefore \] \[p=\frac{8}{\sqrt{5}}\]You need to login to perform this action.
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