A) (1, 1)
B) (-1, 1)
C) (1,-1)
D) (0, 0)
Correct Answer: D
Solution :
Given: \[{{m}_{1}}={{m}_{2}}={{m}_{3}}={{m}_{4}}=1\,kg\] \[AB=BC=CD=DA=1m\] Hence, the co-ordinates of A, B, C, D are given in the figure, from the relation for\[{{x}_{cm}}\] is \[{{x}_{cm}}=\frac{{{m}_{1}}{{x}_{1}}+{{m}_{2}}{{x}_{2}}+{{m}_{3}}{{x}_{3}}+{{m}_{4}}{{x}_{4}}}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}+{{m}_{4}}}\] \[=\frac{1\times 0.5+1\times 0.5+1(-0.5)+1\times (-0.5)}{1+1+1+1}=0\]\[{{y}_{cm}}=\frac{{{m}_{1}}{{y}_{1}}+{{m}_{2}}{{y}_{2}}+{{m}_{3}}{{y}_{3}}+{{m}_{4}}{{y}_{4}}}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}+{{m}_{4}}}\] \[=\frac{1\times 0.5+1\times (-0.5)+1\times (-0.5)+1\times (0.5)}{1+1+1+1}\] Co-ordinates of centre of mass will be (0,0).You need to login to perform this action.
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