A) \[\frac{1}{4}\]
B) \[\frac{1}{2}\]
C) 1
D) 2
Correct Answer: B
Solution :
The equation of motion and particles executing SHM is given by \[\alpha +16{{\pi }^{2}}x=0\] \[\alpha =-16{{\pi }^{2}}x\] But from the relation in SHM, acceleration is given by \[\alpha =-{{\omega }^{2}}x\] So, \[-{{\omega }^{2}}x=-16{{\pi }^{2}}x\] or \[\omega =4\pi \] \[\,\,\,(\because \omega =2\frac{\pi }{T})\] or \[\frac{2\pi }{T}=4\pi \] Hence, \[T=\frac{1}{2}s\]You need to login to perform this action.
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