A) 36
B) 76
C) 108
D) 180
Correct Answer: D
Solution :
Gynoecium of Gloriosa contains 3 carpels. Number of ovules in each carpels = 60 (given) Thus, total number of ovules \[=60\times 3=180\] Percentage of abortive ovules = 27% Percentage of unfertilized ovules =13% Thus, total number of fertilized ovules \[=100-27-13=60%\] So, No of seeds in a cone flower of Gloriosa = 60% of 180 \[=60\times 180/100=108.\]You need to login to perform this action.
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