A) both A and R are true and R is the correct explanation of A
B) both A and R are true but R is not the correct explanation of A
C) A is true but R is false
D) A is false but R is true
Correct Answer: A
Solution :
One mole of \[\text{C}{{\text{H}}_{4}}\] gas is equal to 16 g of \[\text{C}{{\text{H}}_{4}}\] So, at STP \[\because \] 1 mole or 16 g of \[\text{CH}{{ & }_{\text{4}}}\]occupies volume =22.414L \[\therefore \] 8 g of\[\text{CH}{{ & }_{\text{4}}}\] occupies volume \[=\frac{22.414\times 8}{16}=11.207\,L\] Reason: At STP one mole of a gas occupies 22.414L of volume.You need to login to perform this action.
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