A) increases by 36%
B) decreases by 36%
C) increases by 25%
D) decreases by 25%
Correct Answer: C
Solution :
The time period in vibration magnetometer is given by \[{{T}_{1}}=2\pi \sqrt{\frac{I}{{{M}_{1}}B}}\] ?(i) Similarly \[{{T}_{2}}=2\pi \sqrt{\frac{I}{{{M}_{2}}B}}\] ?(ii) Given: \[{{M}_{2}}={{M}_{1}}-\frac{36}{100}{{M}_{1}}\] \[{{M}_{2}}=\frac{64{{M}_{1}}}{100}\] From Eqs.(i) and (ii) \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{64{{M}_{1}}}{100{{M}_{1}}}}=\frac{8}{10}\] or \[\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{10}{8}=1.25\] \[{{T}_{2}}=1.25{{T}_{1}}\]
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