| (A) the capacitance decreases by a factor k |
| (B) the electric field reduces by a factor k |
| (C) the voltage across the capacitor increases by a factor k |
| (D) the charge stored in the capacitor increases by a factor k |
A) A and B are true
B) A and C are true
C) B and C are true
D) B and D are true
Correct Answer: A
Solution :
As capacitance of capacitor after introducing dielectric is given by \[C=\frac{k{{\varepsilon }_{0}}A}{d}\] Hence, if dielectric is introduced the capacitance increases by k, but when dielectric is removed, then capacitance will decrease by factor k and since \[V=\frac{Q}{C}\] Hence, if C decreases in factor k then V will increase by factor k.
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