A) 2.5
B) 5.0
C) 7.5
D) 10.0
Correct Answer: D
Solution :
The induced emf in the coil is \[e=-N\left( \frac{d\text{o }\!\!|\!\!\text{ }}{dt} \right)\] Given \[d\text{o }\!\!|\!\!\text{ =}\,\text{o}{{\text{ }\!\!|\!\!\text{ }}_{2}}-\text{o}{{\text{ }\!\!|\!\!\text{ }}_{1}}=2\times 500\mu \,\,Wb\] \[dt=20\times {{10}^{-3}}\sec \] \[N=200\] \[e=-N\left( \frac{\text{o}{{\text{ }\!\!|\!\!\text{ }}_{2}}-\text{o}{{\text{ }\!\!|\!\!\text{ }}_{1}}}{dt} \right)\] Putting the given values in Eq. (i) \[e=-\frac{200\times 2\times 500\times {{10}^{-6}}}{20\times {{10}^{-3}}}\] \[=-10\,\text{volt }\] \[\Rightarrow \] \[|e|=10\,\text{volt}\]
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