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EAMCET Medical EAMCET Medical Solved Paper-2004

  • question_answer
    The density of an ideal gas is \[0.03\,\text{gc}{{\text{m}}^{-3}}\] Its pressure is \[{{10}^{8}}\,\text{g}\,\text{c}{{\text{m}}^{-1}}\,{{\sec }^{-2}}.\] What is its r. m. s velocity (in cm \[{{\sec }^{-1}}\])?

    A)  \[{{10}^{2}}\]                                   

    B)  \[3\times {{10}^{4}}\]

    C)  \[{{10}^{2}}\]                                   

    D)  \[{{10}^{4}}\]

    Correct Answer: D

    Solution :

                     r. m. s velocity \[=\sqrt{\frac{3P}{d}}\]Where P = pressure \[={{10}^{6}}\]and d = density = 0.03 So, r. m. s velocity \[=\sqrt{\frac{3\times {{10}^{6}}}{0.03}}\]                                 \[=\sqrt{\frac{3\times {{10}^{6}}}{3\times {{10}^{-2}}}}\] \[=\sqrt{{{10}^{8}}}={{10}^{4}}\]


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