A) \[C{{H}_{3}}C{{O}_{2}}{{C}_{2}}{{H}_{5}}\]
B) \[{{C}_{2}}{{H}_{2}}-{{O}_{2}}-{{C}_{2}}{{H}_{5}}\]
C) \[C{{H}_{3}}CHO\]
D) \[C{{H}_{3}}C{{H}_{2}}OH\]
Correct Answer: A
Solution :
\[\text{NaHC}{{\text{O}}_{3}}\]is basic in nature so, it is used in the identification of acid only. In the given compound only ester \[(C{{H}_{3}}COO{{C}_{2}}{{H}_{5}})\] on hydrolysis gives acid as : \[C{{H}_{3}}CO\,OH\xrightarrow{{}}\underset{\text{Acetic}\,\text{acid}}{\mathop{C{{H}_{3}}COOH}}\,\] \[\underset{\text{Ethyl}\,\text{alcohol}}{\mathop{+\,{{C}_{2}}{{H}_{5}}OH}}\,\] So, the correct answer is ethyl acetate.
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